Can $z^*$ be represented using a formula made of elementary functions of $z$?

55 Views Asked by At

Let $z$ be a complex number, and $z^*$ be the complex conjugate. Is it possible to write $z^*$ in terms of $z$ while only using elementary functions like polynomial terms (complex exponents are allowed), exponentials, logarithms and such.

So, $z^* = z - 2\operatorname{Im}(z)$ is not allowed because $\operatorname{Im}(z) = (z - z^*)/2i$ references $z^*$ also and this would be circular. However, if you can write $\operatorname{Im}(z)$ as a formula of $z$ without referring to $z^*$ then, this would be okay.

Similarly, $z^* = |z|^2 /z$ is not allowed less you can write $|z|^2$ in the same way requested above (without referring to $z^*$ itself).

I have an intuitive feeling that this is not possible but can't figure out how to prove it.

1

There are 1 best solutions below

0
On BEST ANSWER

No, this is not possible, principally because elementary functions and compositions, sums, and products thereof are complex differentiable, whereas the map taking $z$ to $z^*$ is not complex differentiable since, for instance, if we try to differentiate at $0$ we see that $$\lim_{z\rightarrow 0}\frac{z^*}z$$ does not exist, since this quantity is $-1$ everywhere on the imaginary axis and $1$ everywhere on the real axis, so lacks a limit at $0$. Indeed, $z^*$ is not complex differentiable anywhere, so you can't even write it in elementary terms on any open set.