Can ZFC decide more values of the Busy Beaver function than PA?

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This is related to a previous question. In that question, I asked whether ZFC can define the Busy Beaver function. I was told even Peano Arithmetic(PA) can define it, and also that PA can't decide that many values of $BB$. Then, can ZFC decide strictly more values of $BB$? I know ZFC can't decide $BB(7918)$.