(Directed & undirected) Cayley graphs of groups have been studied a lot in the literature. I would like to know the answer to the following questions. Please give your valuable suggestions.
- Is there any result which characterize the given group by using its Cayley graph ?'.
i.e., Let Cay(G,S) be a Cayley graph of a group G, where S is a Cayley subset of G. If G' is a group, T is a Cayley subset of G' such that Cay(G',T) $\cong$ Cay(G,S), then G' $\cong$ G.
- Is there any result which characterize 'some properties' of the given group by using its Cayley graph ?'.
This is explained in more detail here: https://terrytao.wordpress.com/2010/07/10/cayley-graphs-and-the-geometry-of-groups/
Some answers to your second question are also given geometric interpretation in that very interesting blog post.
But without coloring non-isomorphic groups can have isomorphic Cayley graphs. For example if $G$ and $G'$ are non-isomorphic group of the same order, and the generating sets are taken to be the full groups in both cases, then the resulting Cayley graphs are always the complete graphs on $|G|$ vertices. The coloring would have remembered the multiplication law (follow the edge colored s from edge a to edge sa, then edge colored t from sa to tsa, then the color of the path from a to tsa is colored (ts)), but without coloring that information is lost (how do we know which edge from sa is "t"?).
(Or anyway to copy more from that blog post so that I learn it better, the concept of a normal subgroup appears geometrically when thinking about Cayley graphs. Suppose $(G,S)$ is a group and a a generating set, and a subgroup $G'$ is generated by $S' \subset S$. Then the Cayley graph $Cay(G,S)$ consists of connected copies of $Cay(G',S')$ (corresponding to the cosets $G'a$). When we put back generators from $S \setminus S'$, these connected components start connecting to each other... if adding a single $s \in S \setminus S'$ connects each component to exactly one other component, then this means that $sG'a = G' b$, which means that multiplying on the left by generators in $S$ maps right cosets of $G'$ to right cosets, which is the same as normality ($x G' x^{-1} = G' b x^{-1}$, and the latter is a coset of $G'$ containing 1, so is $G'$... while in the other direction if $G'$ is normal, then $aHb = aHa^{-1} a b = Hab$.))