I am a little stumped by what this question is asking.
A large playlist consists of songs with times which have mean 2 minutes ten seconds and standard deviation 15 seconds. What is the probability than more than 36 randomly chosen songs are required to fill a program which is 76 minutes long?
Would the equation I have to use to find Z be (76 - 2.167(36))/(.25*6)? Than subtract the z-value from 1? I am not sure that I am doing this right
Find the MGF of $X_1+....+X_{36}$ which will be distributed normally with something like $N(72m,1.5m)$, standardize..ie$(76-72)/1.5$, and take out your tables.