The question I am working on is asking- Use the chain rule to calculate $\frac{\partial F}{\partial s}$ and $\frac{\partial F}{\partial t}$ for the given function F:
$$F(s,t)=f(x(s,t),y(s,t))$$ where $$f(x,y)=2x^2y-xy^2$$ $$x(s,t)=t^2+3s^2$$ and $$y(s,t)=3st$$
This is what I have done
$\frac{\partial F}{\partial s}$=$\frac{\partial F}{\partial x}$*$\frac{\partial x}{\partial s} = (4xy-y^2)*(6s)$
and
$\frac{\partial F}{\partial t}$=$\frac{\partial F}{\partial y}$*$\frac{\partial y}{\partial t} = (2x^2-2yx)*(3s)$
Is my work correct ?


Hint: When dealing with partial fractions, all terms must come into account. For example: $$\frac{\partial F}{\partial s}(s,t) = \frac{\partial f}{\partial x}(x(s,t),y(s,t))\cdot \frac{\partial x}{\partial s}(s,t)+\frac{\partial f}{\partial y}(x(s,t),y(s,t))\cdot \frac{\partial y}{\partial s}(s,t).$$ Now just plug in everything there. For $\frac{\partial F}{\partial t}(s,t)$ is is the same thing.