change to logarithmic form. solve for P.
(2/3)log(R) + 0.05 = log(P)
the base is 10 for both logs. How do I answer this?
Write this as $\log(P) =\log(R^{2/3}10^{0.05}) $.
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Write this as $\log(P) =\log(R^{2/3}10^{0.05}) $.