characteristic equation doubts

37 Views Asked by At

I am a newbie in matrix algebra, struggling with some basic concepts:

characteristic equation

I do not understand from the above matrix(2x2) example:

  • How is it possible the above to be true?, multiplying by the identity matrix, means that the position row 2, col 1, will always be 0. And in A, the value of row 2, col 1, is 1... Therefore, it will always be $1-0$ regardless of the value of $\lambda$ I choose.

  • When I do operations in matrices, ie: A - B. I thought the result was a matrix, (I "loop" through them doing the position to position A - B). So, how come in the above equation it returns a scalar 0? or is 0 a matrix with all 0 values?

I know my reasoning must be wrong somewhere, but not sure where.