We can bring a function of the form $$ax^2+2bxy+cy^2+dx+ey+f=0$$
To the form of $$\lambda_{1}(x'')^2+\lambda_{2}(y'')^2+k=0$$ In a textbook It is written that if:
$\lambda_{1}\lambda_{2}>0$ and the sign of $k$ is opposite to this of $\lambda_{1}$ it is an ellipse
$\lambda_{1}\lambda_{2}>0$ and the sign of $k$ is same to this of $\lambda_{1}$ it is an empty set
$\lambda_{1}\lambda_{2}>0$ and $k=0$ it is a point
$\lambda_{1}\lambda_{2}>0$ and $k\neq 0$ it is an hyperbola
$\lambda_{1}\lambda_{2}>0$ and $k=0$ it is two straight lines
But (1) can be (4) and (5) can be (3)
As serg_1 notes, two of the relation signs are not OK. Correct statements are:
$\lambda_{1}\lambda_{2}>0$ and the sign of $k$ is opposite to this of $\lambda_{1}$ it is an ellipse
$\lambda_{1}\lambda_{2}>0$ and the sign of $k$ is same to this of $\lambda_{1}$ it is an empty set
$\lambda_{1}\lambda_{2}>0$ and $k=0$ it is a point
$\lambda_{1}\lambda_{2}<0$[** N.B. "$<$"] and $k\neq 0$ it is an hyperbola
$\lambda_{1}\lambda_{2}<0$[** N.B. "$<$"] and $k=0$ it is two straight lines