How to check whether $\sin(t)\over t$ is a characteristic function or not?
If $\sin(t)\over t$ is a distribution function.
It is not a distribution function because it takes negative values. It is the characteristic function of uniform distribution on $(-1,1)$. Unfortunately, there is no practical way of determining whether a given function is a characteristic function.
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It is not a distribution function because it takes negative values. It is the characteristic function of uniform distribution on $(-1,1)$. Unfortunately, there is no practical way of determining whether a given function is a characteristic function.