Check if the functional is continuous

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Check if following funtional is continuous

$ P\ni p \to q \in P : q'=p , q(0)=0$ where $ P $ is polynomials space

towards norms:

1) $||p|| = sup{|p(t)|: t ∈ [0, 1]}$

2)$||p|| = \int\limits_{0}^{1}{|p(t)|: t ∈ [0, 1]}$

if so, compute its norm.

I've started:

1)$||p|| = sup_{sup{|p(t)|\le1}}\{sup{|q(t)|: t ∈ [0, 1]}\}$

2) $ ||p|| = sup_{\int\limits_{0}^{1}{|p(t)|\le1}}\{\int\limits_{0}^{1}{|q(t)|: t ∈ [0, 1]}\} $

But I don't know how to continue. Could I ask for help?

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Let's call $\varphi$ the functional and $\Vert p \Vert_\infty$ the norm $\sup\limits_{t \in [0,1]} \vert p(t) \vert$.

For (1), you have for all $t \in [0,1]$ $$[\varphi(p)](t) = \int_0^t p(s) \ ds$$ hence $$\vert [\varphi(p)](t) \vert = \left\vert \int_0^t p(s) \ ds \right\vert \le \int_0^t \Vert p \Vert_\infty \ ds = t \Vert p \Vert_\infty \le \Vert p \Vert_\infty.$$ Therefore $$\Vert \varphi(p) \Vert_\infty \le \Vert p \Vert_\infty$$ which proves the continuity of $\varphi$ for the norm $\Vert \cdot \Vert_\infty$.

Taking for $p$ the polynomial function $p_1$ which is constant and equal to $1$ you have $\Vert p_ 1 \Vert_\infty = 1$ and $\Vert \varphi(p_ 1) \Vert_\infty = 1$. Therefore the norm of $\varphi$ related to $\Vert \cdot \Vert_\infty$ is equal to $1$.

Regarding (2) and denoting $\Vert p \Vert_1$ the norm $\int_0^1 \vert p(t) \vert \ dt$, we have: $$\Vert \varphi(p) \Vert_1 = \int_0^1 \left\vert \int_0^t p(s) \ ds \right\vert \ dt \le \int_0^1 \left( \int_0^t \vert p(s) \vert \ ds \right) \ dt \le \int_0^1 \left( \int_0^1 \vert p(s) \vert \ ds \right) \ dt = \Vert p \Vert_1.$$ So $\varphi$ is also continuous related to the norm $\Vert p \Vert_1$.