If x ≥ 3 and G is not a tree, show that $χ(G, x) < x(x−1)^{n−1}$
I think if G is connected, the result is trivial.
How can I deal with the case that G is not connected?
If x ≥ 3 and G is not a tree, show that $χ(G, x) < x(x−1)^{n−1}$
I think if G is connected, the result is trivial.
How can I deal with the case that G is not connected?
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In my answer to the Chromatic polynomial of connected graph $ \leq x(x-1)^{n-1}$, I explain how it's not true for the polynomials (giving a counterexample).
It's true if we restrict to non-negative integers, but this means we're counting $x$-colorings for $x \geq 0$ (and the polynomial is just a distraction).
In this question, $\chi(G, x) < x(x−1)^{n−1}$ is not true when $G$ is a tree. After changing $<$ to $\leq$ and restricting to non-negative integers, yes, it's not difficult (a $x$-coloring of $G$ gives an $x$-coloring of a spanning tree).
If we allow $G$ to be a disconnected graph, then it's not true even when $x$ is restricted to positive integers. An $n$-vertex graph with no edges has the chromatic polynomial $x^n$.