how can i find the formula for the nth term of this series?
SQ = square root
$\sqrt{1} = 1$
$\sqrt{1 +\sqrt{4}} = \sqrt{3}$
$\sqrt{1 +\sqrt{4+\sqrt{9}}} \approx 1.909385061$
$\sqrt{1 +\sqrt{4+\sqrt{9+\sqrt{16}}}} \approx 1.938508807$
$\sqrt{1 +\sqrt{4+\sqrt{9+\sqrt{16+\sqrt{25}}}}} \approx 1.942232028$
$\sqrt{1 +\sqrt{4+\sqrt{9+\sqrt{16+\sqrt{25+\sqrt{36}}}}}} \approx 1.942619065$
$\sqrt{1 +\sqrt{4+\sqrt{9+\sqrt{16+\sqrt{25+\sqrt{36+\sqrt{49}}}}}}} \approx 1.942652736$