(Co)homology of $S^2×S^2/ℤ_2$

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Cohomology of $S^2\times S^2/\mathbb{Z}_2$

I was looking at this question, the accepted answer uses the homology of the space to find the cohomology. I was wondering how one could compute the homology of an orbit space like this in the first place?

"The product of two spheres admits a diagonal $ℤ_2$ action, $(x, y)\mapsto(−x,−y)$" - describe the homology groups of the orbit space of this free action.