Combinational meaning of $\sum\limits_{k=r}^{n} {k \choose r }={{n+1} \choose r+1}$

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What's the combinational interpretation of the identity $\sum\limits_{k=r}^{n} {k \choose r }={{n+1} \choose r+1}$?

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we want choose r+1 persons from n+1 persons let A(1), A(2),..., A(n+1) are that n+1 persons first we count the numbers of choices that A(1) is choosed that equals to (r,n) second we count the numbers of choices that A(1) is not choosed but A(2) is choosed that equals to (r,n-1) third... and sum of these is equal to (r+1,n+1)