$\left.\frac12i\;\text{Log}\frac{1-(-i+e^{it})}{1+(-1+e^{it})}\right|_0^{2\pi}=\frac12i\left(\log\left|\frac{i}{i}\right|+i\arg 1-\log|1|-i\arg1+2\pi ik\right)$
could someone explain how this is equal, and how we get from the LHS to the RHS.
2026-03-28 22:06:33.1774735593
Complex integration, limits, arctan
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