Euler's Law addition, Finding the real and imaginary parts of $\ z_1^2+ jz_2 $
Where $\ z_1=e^{j\pi/4} $ and $\ z_2=e^{-j\pi/3} $
I don't really understand this question, but I did some working:
$\ z_1^2 = e^{\pi/2} $
$\ z_1^2+jz_2 = e^{j\pi/2}+e^{-j\pi/2} $
$\ = 2\cos{\pi/2-\pi/3} = \sqrt{3} $
So I don't know what to do now.
HINT generalize the problem, when $\text{z}_1\space\wedge\space\text{z}_2\in\mathbb{C}$:
$$\text{Q}=\text{z}_1^2+\text{z}_2i=\left(\Re[\text{z}_1]+\Im[\text{z}_1]i\right)^2+\left(\Re[\text{z}_2]+\Im[\text{z}_2]i\right)i$$
Now, we can set:
So, for $\text{Q}$ we know:
$$\Re\left[\text{Q}\right]=\Re\left[\text{z}_1^2+\text{z}_2i\right]=\Re^2[\text{z}_1]-\Im^2[\text{z}_1]$$
$$\Im\left[\text{Q}\right]=\Im\left[\text{z}_1^2+\text{z}_2i\right]=2\Re[\text{z}_1]\Im[\text{z}_1]$$
Now, using Euler's formula we can write $\text{z}$ when $\text{z}\in\mathbb{C}$:
$$\text{z}=\Re[\text{z}]+\Im[\text{z}]i=|\text{z}|e^{\left(\arg(\text{z})+2\pi k\right)i}=|\text{z}|\cos(\arg(\text{z})+2\pi k)+|\text{z}|\sin(\arg(\text{z})+2\pi k)i$$
Where $|\text{z}|=\sqrt{\Re^2[\text{z}]+\Im^2[\text{z}]}$, $\arg(\text{z})$ is the complex argument of $\text{z}$ and $k\in\mathbb{Z}$.