complex residue involving exponent of quotient of polynomials

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I was trying to work out an integral and came to trying to find the complex residue of

$$R = \exp\left(\frac{Ax^2 + Bix}{Dx + 1}\right)$$

at $x = -D^{-1}$. I used partial fractions to get:

$$ = \exp\left( \frac{- B Di + A}{D^2 (D x + 1)} + \frac{B Di + A D x - A}{D^2} \right)$$

If I try to use limits to find the coefficient:

$$\lim_{x \rightarrow -D^{-1}}\quad (Dx + 1)\exp\left(\frac{Ax^2 + Bx + C}{Dx + 1}\right)$$

$$ = \lim_{x \rightarrow -D^{-1}}\quad (Dx + 1)\exp\left( \frac{- B Di + A}{D^2 (D x + 1)} + \frac{B Di + A D x - A}{D^2} \right)$$

$$ = \exp\left(\frac{BDi - 2A}{D^2}\right)\lim_{x \rightarrow -D^{-1}}\quad (Dx + 1)\exp\left( \frac{- B Di + A}{D^2 (D x + 1)} \right)$$

which leaves finding:

$$\lim_{x \rightarrow -D^{-1}}\quad (Dx + 1)\exp\left( \frac{K}{(D x + 1)} \right)$$

I'm not even sure this limit is defined. Is there a better way to find this residue?

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The singularity at $-D^{-1}$ is an essential singularity, so you cannot determine the residue using a method to find residues in poles.

Here, writing $w = x+D^{-1}$, polynomial division gives you an expression of the form

$$\exp\left(\frac{a}{w} + b + cw\right)$$

whose residue in $0$ you want to determine. The constant can be pulled out, so the relevant part is $\exp\left(\frac{a}{w}+cw\right)$. You can find it by expanding it into a series in powers of $\frac{a}{w}+cw$, and from each term collecting the contribution to $w^{-1}$. In my opinion better is to expand $e^{a/w}$ and $e^{cw}$ separately, and obtain the overall coefficient via the product of the two Laurent series. We find

$$\left(\sum_{n=0}^\infty \frac{a^n}{n!w^n}\right)\left(\sum_{m=0}^\infty \frac{c^mw^m}{m!}\right) = \sum_{k=-\infty}^\infty \left(\sum_{m=\max\{0,k\}}^\infty\frac{c^ma^{m-k}}{m!(m-k)!}\right)w^k,$$

for the residue, $k = -1$,

$$\operatorname{Res}\left(e^{a/w+cw}; 0\right) = \sum_{m=0}^\infty \frac{c^ma^{m+1}}{m!(m+1)!},$$

which is closely related to the modified Bessel function of the first kind, the value is

$$\sqrt{\frac{a}{c}} I_1(2\sqrt{ac}).$$

Remember that we ignored the constant $b$ so far, then we obtain

$$\operatorname{Res}\left(\exp\left(\frac{a}{w} + b + cw\right);0\right) = e^b\sqrt{\frac{a}{c}} I_1(2\sqrt{ac}).$$

Long division yields

$$a = \frac{A}{D},\quad b = \frac{BDi-2A}{D^2},\quad c = \frac{A-BDi}{D^3}$$

here (if I haven't miscalculated).