If the question is not clear, then assume $t=\log(\log n)$, then the question can be re-framed as $\text{O}(t^{10})$ vs $O(t^5)$? So which has a higher order of growth?
Thanks.
2026-05-14 15:00:38.1778770838
Complexity $\text{O}\left(\log(\log n))^{10}\right)$ vs $\text{O}\left((\log(\log n))^5\right)$?
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$t$ goes to infinity, though slowly.
Therefore $t^{10}$ grows faster than $t^5$.