Composition of Ordered Pair

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I'm doing math exercises from a Computer Science book and I am confused as to how the following result (from the solutions manual) is obtained:

Given the function f={(a,b), (a,c), (c,d), (a,a), (b,a)}

The composition of f with itself: f(f(x)) = {(a,a), (a,b), (a,c), (a,d), (b,a), (b,b), (b,c)} .

By matching the y-values of the first function with the x-values of the second function, I managed to get all the pairs in the above answer accept for (b, b) and (b, c). Does anyone know what I've done wrong? Thanks for the help.

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As this relation's defined, we see that $(a,b)\in f$ and $(b,a)\in f$ so $f(\color{red}a)=b$ and $f(b)=\color{red}a$ respectively. So $f(f(b))=f(\color{red}a)=b$. This means that $(b,b)\in f$.