Let $v=v_kdx^k$,$R_{ijkl}=g_{kp}R^p_{ijl}$,How to show that :
$$ \nabla_i\nabla_jv_k-\nabla_j\nabla_iv_k=R_{ijkl}g^{lm}v_m $$
Let $v=v_kdx^k$,$R_{ijkl}=g_{kp}R^p_{ijl}$,How to show that :
$$ \nabla_i\nabla_jv_k-\nabla_j\nabla_iv_k=R_{ijkl}g^{lm}v_m $$
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Hint: Using the defintion of $R$, write $R_{ijk}^l$ in terms of $\Gamma_{ij}^k$ and its derivatives. Then your formula can be proved by direct computation, using
$$\nabla_i v_j = \partial_iv_j - \Gamma_{ij}^k v_k.$$