Conditional mean of Gaussian RV given its absolute value is greater than a constant.

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Suppose $X\sim N(0,\sigma^2)$, is there a closed form expression for $\mathbb{E}(X \mid |X|>A)$?

Thanks in advance!

Intuitively, I think it is zero given we are removing mass around 0 symmetrically, but haven't managed to prove it.