Conditions under which an Convolution operator is normal.

482 Views Asked by At

I have a possibly complex valued convolution operator given by

$ \int_{\mathbb{R}}K(x-y)f(y)dy$

I know that the operator is self-adjoint if

$K(x)=\overline{K(-x)}$

holds. But are there softer conditions under which the operator is only normal? Every time I want to find conditions I only get the same as in the self-adjoint case.

Thanks for all ideas and helps.