Here are the solution I have worked out. Is it correct?
Given $C + BC'$:
- $C + B' + C'$
- $C + (B'+C')'$
- $C + B + C$
- $C (C + B + C)$.
Is the answer (2)?
Here are the solution I have worked out. Is it correct?
Given $C + BC'$:
- $C + B' + C'$
- $C + (B'+C')'$
- $C + B + C$
- $C (C + B + C)$.
Is the answer (2)?
$$Given: C + B\overline C = C (1 + B) + B\overline C = C + BC + B\overline C = C + B (C + \overline C) = B + C$$ $$1.\ C + \overline B + \overline C = \overline B + (C + \overline C) = \overline B + 1 = 1$$ $$2.\ C + \overline {(\overline B + \overline C)} = C + BC = C (1 + B) = C$$ $$3.\ C + B + C = B + C$$ $$4.\ C (C + B + C) = CC + BC + CC = C + BC + C = C (1 + B + 1) = C$$
Reduce them all and the answer has to be 3.
Laws and Theorems of Boolean Algebra