I read Emily Riehl's Category theory in Contex, but I can't grasp the book's definition of (strict) create coequalizers of U-split pairs. Can someone describe these two definitions in clear and strict language? I implore everyone's help.enter image description here
2026-05-15 20:55:30.1778878530
Confused about the definition of (strict) create coequalizers of U-split pairs
49 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
1
There are 1 best solutions below
Related Questions in CATEGORY-THEORY
- (From Awodey)$\sf C \cong D$ be equivalent categories then $\sf C$ has binary products if and only if $\sf D$ does.
- Continuous functor for a Grothendieck topology
- Showing that initial object is also terminal in preadditive category
- Is $ X \to \mathrm{CH}^i (X) $ covariant or contravariant?
- What concept does a natural transformation between two functors between two monoids viewed as categories correspond to?
- Please explain Mac Lane notation on page 48
- How do you prove that category of representations of $G_m$ is equivalent to the category of finite dimensional graded vector spaces?
- Terminal object for Prin(X,G) (principal $G$-bundles)
- Show that a functor which preserves colimits has a right adjoint
- Show that a certain functor preserves colimits and finite limits by verifying it on the stalks of sheaves
Trending Questions
- Induction on the number of equations
- How to convince a math teacher of this simple and obvious fact?
- Find $E[XY|Y+Z=1 ]$
- Refuting the Anti-Cantor Cranks
- What are imaginary numbers?
- Determine the adjoint of $\tilde Q(x)$ for $\tilde Q(x)u:=(Qu)(x)$ where $Q:U→L^2(Ω,ℝ^d$ is a Hilbert-Schmidt operator and $U$ is a Hilbert space
- Why does this innovative method of subtraction from a third grader always work?
- How do we know that the number $1$ is not equal to the number $-1$?
- What are the Implications of having VΩ as a model for a theory?
- Defining a Galois Field based on primitive element versus polynomial?
- Can't find the relationship between two columns of numbers. Please Help
- Is computer science a branch of mathematics?
- Is there a bijection of $\mathbb{R}^n$ with itself such that the forward map is connected but the inverse is not?
- Identification of a quadrilateral as a trapezoid, rectangle, or square
- Generator of inertia group in function field extension
Popular # Hahtags
geometry
circles
algebraic-number-theory
functions
real-analysis
elementary-set-theory
proof-verification
proof-writing
number-theory
elementary-number-theory
puzzle
game-theory
calculus
multivariable-calculus
partial-derivative
complex-analysis
logic
set-theory
second-order-logic
homotopy-theory
winding-number
ordinary-differential-equations
numerical-methods
derivatives
integration
definite-integrals
probability
limits
sequences-and-series
algebra-precalculus
Popular Questions
- What is the integral of 1/x?
- How many squares actually ARE in this picture? Is this a trick question with no right answer?
- Is a matrix multiplied with its transpose something special?
- What is the difference between independent and mutually exclusive events?
- Visually stunning math concepts which are easy to explain
- taylor series of $\ln(1+x)$?
- How to tell if a set of vectors spans a space?
- Calculus question taking derivative to find horizontal tangent line
- How to determine if a function is one-to-one?
- Determine if vectors are linearly independent
- What does it mean to have a determinant equal to zero?
- Is this Batman equation for real?
- How to find perpendicular vector to another vector?
- How to find mean and median from histogram
- How many sides does a circle have?
It might help to see the motivating example of a $U$-split coequalizer pair. For this example, let $M$ be a monoid, and consider the functor $U : M\text{-}\mathbf{Set} \to \mathbf{Set}$ as the underlying set functor. We then claim that for any $M$-set $S$, $S$ is the coequalizer of the two maps $M \times M \times S \to M \times S$ (where each is an $M$-set via $M$ acting on the first element): $(m, m', s) \mapsto (m m', s)$ and $(m, m', s) \mapsto (m, m' \cdot s)$.
The proof? For $m \in M$ and $s \in S$, consider the element $(e, m, s) \in M \times M \times X$. The first map sends this to $(m, s)$ and the second map sends this to $(e, m \cdot s)$. Therefore, in the coequalizer, the images of $(m, s)$ and $(e, m \cdot s)$ must become equivalent. Conversely, the fact that $M \times S \to S, (m, s) \mapsto s$ does coequalize the two maps $M \times M \times S \to M \times S$ implies that the images of $(e, s)$ and $(e, s')$ become equal if and only if $s = s'$.
The idea of a split coequalizer is to generalize this by considering the maps $M \times S \to M \times M \times S, (m, s) \mapsto (e, m, s)$ and $S \to M \times S, s \mapsto (e, s)$, and extracting the properties of these maps that make the argument in the previous paragraph work. However, notice that these maps are not $M$-equivariant; so they only make sense as morphisms in $\mathbf{Set}$ and not as morphisms in $M\text{-}\mathbf{Set}$. This is why we consider coequalizer pairs in $M\text{-}\mathbf{Set}$ where there are a couple additional functions after applying $U$ which make the fact of the coequalizer clear (though only at the set level) in a category-theoretical way.
Now a proof that a general $U$-split coequalizer pair has a coequalizer in $M\text{-}\mathbf{Set}$ is straightforward; and strictly creating coequalizers of $U$-split pairs corresponds to the fact that there is a unique way to put an $M$-set structure on the set-level coequalizer. This proof would very easily generalize to one direction in the proof of Beck's monadicity theorem, so I will not bother to reproduce that here. (And incidentally, it's easy to see from the argument above where the other direction in the proof comes from: the generalization of $s \mapsto (e, s)$ is the unit $\eta$ of the monad, and the generalization of $(m, s) \mapsto (e, m, s)$ is $\eta T$.)