Confusion about infinite order groups, subgroups and comparing order between them.

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I was given feedback for a homework problem,

Let $G$ be a group. Let $H$ be a subgroup of $G$. Let $a \in G$. Let $Ha$ be a subgroup of $G$.

The problem was to show that $Ha = H$.

I established that $H \subset Ha$ and then I made the argument that since $Ha = \{ha \vert h \in H\}$, $\vert Ha \vert \leq \vert H \vert$ so $H = Ha$

I was marked wrong and given the justification that $\vert Ha \vert \leq \vert H \vert$ isn't valid if $\vert H \vert = \infty$

I wanted to understand why, as I think the point still holds that $Ha$ can have at most as many elements as $H$, so if $H$ is a subset of $Ha$ then $H = Ha$.