I read that for right exact functors we consider left derived functors and the resolutions that we consider are projective resolutions...
I read that for left exact functors we consider right derived functors and the resolutions that we consider are injective resolutions...
This i read in M.Scott Osborne's Basic homological algebra book in section 6.2 http://www.amazon.com/Basic-Homological-Algebra-Graduate-Mathematics/dp/038798934X
But in Serre's Local fields in chapter seven he said that $A^G$ is left exact which means he should consider injective resolutions for right derived functors but he considered Projective resolutions..
He said in section 2 of chapter 7 that :
By definition, the right derived functors of the functor $A^G$ are cohomology groups of $G$ with coefficients in $A$. Recall briefly how they are computed.
choose a resolution of the $G$- module $\mathbb{Z}$ by Projective $G$ modules
I got confused with this approach..
please let me know what i am missing..
What he is doing is the following.
First, he knows there is an isomorphism $A^G=\hom_G(\mathbb Z,A)$, so the derived functors of $(-)^G$ are the derived functors of $\hom_G(\mathbb Z,-)$, which are exactly $\operatorname{Ext}_G(\mathbb Z,-)$.
Second, to compute $\operatorname{Ext}_G(\mathbb Z,A)$ he knows he can either use an injective resolution of $A$ and apply to it the functor $\hom_G(\mathbb Z,-)$, or take a projective resolution of $\mathbb Z$ and apply to it the functor $\hom_G(-,A)$.
Well: he picks the second option.