Congruence in localization of rings

47 Views Asked by At

Please help me to prove for all maximal ideals $\mathfrak{m}$ of $R$, $(aR/a^2R)_\mathfrak{m}\cong (aR)_\mathfrak{m}/(a^2R)_\mathfrak{m}\cong aR_\mathfrak{m}/a^2R_\mathfrak{m}$, where $R$ is a commutative ring with 1 and $a\in R$.

1

There are 1 best solutions below

2
On

This is because localization is exact.