Is it known whether or not there exist arbitrarily long sequences of consecutive zeros in the decimal expansion of $\pi$?
2026-04-06 01:22:34.1775438554
On
Consecutive zeros in decimal expansion of $\pi$
996 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
2
There are 2 best solutions below
0
On
There are conjectures saying so. The result is unknown. Anyway, taking a random number in every interval without preference, you find such a number with probability one. There are known nombers with such a property, such as the Champernowne constant
It is "known" but not known. It is "known" because $\pi$ is expected to be normal. Almost all reals are and there is no known reason for $\pi$ not to be. Being normal implies (among many other things) that sequences of zeros occur at their statistical expectation-that a string of $n$ zeros will occur on average every $10^{n}$ digits. But the normality of $\pi$ has not been proven.