Consider the series of functions
$$ \sum_{n=1}^{\infty} \frac{1}{n} \left( \frac{1}{2}\sin(x) \right)^n $$
Does this series converge simply/absolutely/uniformly/normally on $\mathbb{R}$?
My attempt:
I tried to prove that this series converges normally (which would imply the other 3), but I found that it wasn't because $ \sum_{n=1}^{\infty} \frac{1}{n} $ is divergent.
Then I found that it converges pointwise in $x=0+k\pi$ to the null function.
I also found that it isn't uniformly convergent.
I'm thinking this could be completely wrong, which is why I'm trying to get some help. Thanks in advance!
That series is normally convergent on $\Bbb R$: $\sup_{x\in\Bbb R}\left|\frac1n\left(\frac12\sin(x)\right)^n\right|=\frac1{n2^n}$ and the series $\sum_{n=1}^\infty\frac1{n2^n}$ converges.