Given a Hilbert space $\mathcal{H}$.
Suppose one has: $$\|\varphi\|=\lim_n\|\varphi_n\|$$ Then it follows: $$\varphi\rightharpoonup\varphi\implies\varphi_n\to\varphi$$
How can I check this?
Given a Hilbert space $\mathcal{H}$.
Suppose one has: $$\|\varphi\|=\lim_n\|\varphi_n\|$$ Then it follows: $$\varphi\rightharpoonup\varphi\implies\varphi_n\to\varphi$$
How can I check this?
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Well... you just have to show $\|\varphi_n - \varphi\| \to 0$. But $$\|\varphi_n-\varphi\|^2 = \|\varphi_n\|^2 - \langle \varphi_n,\varphi\rangle -\langle \varphi,\varphi_n\rangle + \|\varphi\|^2.$$
Now, by assumption the first term converges to $\|\varphi\|^2$, the second and third term converge (by assumption of weak convergence) to $\langle \varphi,\varphi\rangle=\|\varphi\|^2$.