Converting $antilog$ into exponential form

Question

$$log_a (x) = y$$

$$\Rightarrow x = a^{y}$$

Similarly, if $$antilog_a (y) = x$$ How will it be written in exponential form?

Answer 1

By definition, the anti-log is the inverse of the log:

$$\operatorname{antilog}_a(y)=x$$

Take the log of both sides:

$$\log_a(\operatorname{antilog}_a(y))=\log_a(x)$$

They cancel, and we are left with

$$y=\log_a(x)$$

Answer 2

Since the anti-log is the inverse of the log: $${antilog}_a(y)=x$$ Taking log both the sides: $$\log_a(x)=\log_a({antilog}_a(y))$$ The $\log$ and $anti\log$ will cross each other $$y=\log_a(x)$$ Hence, $$a^y=x$$

Answer 3

If $$antilog_a(y) = x $$ $$\Rightarrow a^{y} = x $$

credit: John & J. M from the comments