I have the given equation:
$r^3=2 \sin(\phi+\theta)$,
where $\theta$ = $\arccos(1/\sqrt{3})$ and $\phi$ is not given.
If I want to convert it to Cartesian form, is it simply sufficient to interpret $r=\sqrt{x^2+y^2}$ and derive that $\phi=\pi-\theta$?
The problem is that I cannot be sure that $\phi=\pi-\theta$. Does this always regard trigonometric functions?