I want to show that $$ e^{\alpha t} ∗ e^{\beta t} = \frac{e^{\alpha t} − e^{\beta t}}{\alpha − \beta}, \quad \forall \alpha \ne \beta $$
I just know that : $(f ∗ g)(t) = \int_0^t f(t − s) g(s) ds$
Does anybody have an idea?
I want to show that $$ e^{\alpha t} ∗ e^{\beta t} = \frac{e^{\alpha t} − e^{\beta t}}{\alpha − \beta}, \quad \forall \alpha \ne \beta $$
I just know that : $(f ∗ g)(t) = \int_0^t f(t − s) g(s) ds$
Does anybody have an idea?
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So when you plug into your definition, you let $f(t) = e^{\alpha t}$ and $g(t) = e^{\beta t}$, and you get $$ (f*g)(t) = \int_0^t e^{\alpha(t-s)}e^{\beta s}ds = e^{\alpha t} \int_0^t e^{s(\beta - \alpha)}ds $$
Can you finish?