Could a differential form be both exact and co-exact?

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If my understanding is correct, on a closed manifold, the exact forms and co-exact forms are disjoint, but I'm not sure about the differential forms on manifolds with boundary. Could there be a differential form that is both exact and co-exact on a manifold with boundary? I'm particularly interested in 2D manifolds with boundary (i.e. surfaces with boundary).

Thanks.