$$\sum\limits_{n=2}^\infty \frac{\cos(n\pi)}{\ln(n)^2}$$
I'm not sure how this would conditionally converge, according to my calculations I would assume it's absolutely converge.
$$\sum\limits_{n=2}^\infty \frac{\cos(n\pi)}{\ln(n)^2}$$
I'm not sure how this would conditionally converge, according to my calculations I would assume it's absolutely converge.
Copyright © 2021 JogjaFile Inc.
Note that $\cos(n\pi) = (-1)^n$.
This converges by the alternating series test. Compare to the harmonic series to see that it does not converge absolutely.