Conic: hyperbola, Vertices: $(5,\pi/2)$,$(2,\pi/2)$
What I did is found the center to be $(7/2,π/2)$, so $c=7/2$, $a=3/2$, $e=(7/2)/(3/2)=7/3$.
Then the horizontal directrix above the pole
$r=(7/3)p/[1+7/3\sinθ]$
$r=7p/[3+7\sin(π/2)]=1$, $p=10/7$
$r=10/[3+7\sinθ]$
Can someone help with where I went wrong? Thanks!