It is well known that if \begin{equation} S_{1}=\sum_{n=1}^{\infty} F_{n} \end{equation} converges, then \begin{equation} S_{2}=\sum_{n=1}^{\infty} F_{2n-1}+F_{2n} \end{equation} converges
But I know that given that $S2$ converges then $S1$ may diverges.
Why is that true? Could someone give me a counterexample to let me see the fact? Or could someone give me a hint to build up such an counterexample? Many thanks!
Consider $F_n=(-1)^n$. Then we have
$$S_2=\sum_{n=1}^\infty(-1)^{2n-1}+(-1)^{2n}=0+0+0+\dots0=0$$
On the other hand,
$$S_1=\sum_{n=1}^\infty(-1)^n=-1+1-1+1-1+1-1+\dots$$
which doesn't converge to anything.