I'm having a little problem with a statistics problem I am working on. I'm not really sure where to start to prove the two statements. Any help would be greatly appreciated.
Let $x$ and $y$ be jointly distributed numeric variables and let $z = a + by$, where $a$ and $b$ are constants.
Show that $\text{cov}(x, z) = b\, \text{cov}(x, y)$.
Show that if $b > 0, \text{cor}(x, z) = \text{cor}(x, y)$.
I would start with $$\text{Cov}(X,Z) = E[XZ]-E[X]E[Z],$$ and recall that $Z =a+bY$. Alternatively, $$\text{Cov}(X, Z) = \text{Cov}(X,a+bY)$$ and use bilinearity properties.
I would use $$\text{Corr}(X,Z) = \frac{\text{Cov}(X,Z)}{\text{SD}(X)\text{SD}(Z)}=\frac{\text{Cov}(X,a+bY)}{\text{SD}(X)\text{SD}(a+bY)}.$$