I can't seem to figure out how to take word problems and convert them into a solvable simultaneous equation.
A rectangle has an area of 66.49metres^2. The width of the rectangle is 6.75 metres shorter than the length.
(1)Form a quadratic equation to represent this information.
(2)Use this equation to find both the length and the width of the rectangle
So far the only thing i'm getting is that the width = length-6.75, so W=L-6.75
Hint
Let $L $ be the length.
the width will be $l=L-6.75$.
the area is then
$L (L-6.75)=66.49$.