A parabolic satellite dish has a cross section that can be modelled by the equation $$y = 0.05\,x^2.$$ While still in the shipping yard, the dish fills with rain. The rain forms a circular puddle with a diameter of $2$m. What is the depth of the water at the centre of the dish?
2026-03-31 16:55:31.1774976131
Cross section of parabolic satellite in Quadratic Functions
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$y = 0.05x^2$. If you fix the bottom apex of the dish is (0,0). The diameter of the circular puddle is 2m. The value of x = 1 (diameter/2). Substitute the value of x to find the value of y = 0.05*1 = 0.05. The depth of water at the center of the dish is 0.05m.