Is it possible to express the cube root of "i" without using "i" itself?
If this is possible can you show me how to arrive at it?
thanks
Is it possible to express the cube root of "i" without using "i" itself?
If this is possible can you show me how to arrive at it?
thanks
On
No. $i$ has 3 cube roots in the complex numbers and none of them can of course be real (i.e. have no imaginary part; a real number has a real third power, not $i$). They are
$$e^{i\frac{\pi}{6}}, e^{i\frac{5\pi}{6}}, e^{i\frac{3\pi}{2}} $$
which you can write out using Euler's $e^{it} = \cos(t) + i\sin(t)$ as usual.
On the unit circle mark the $30$ degree, $150 $ degree and $270$ degree points. These are the cube roots of $i$