I've just been going over some stuff I should actually already know - and I've come to a question that has really stumped me, (my math skill are lacking) and I don't actually know where to begin on it.
Which of the following minterms is $$m_3(A,B,C)$$
1. ¬ABC
2. A¬BC
3. AB¬C
4. ABC
I'm less interested in the answer, and more in 'how' the answer is achieved
Thanks - Apologies for the janky formatting
Edit:
I've just been given the 'answer' after I got it incorrect (I guessed) of -
3 = 0112, thus the first variable A must be complemented and the other two (B and C) must remain non-complemented.
Now I'm even more confused!
It seems more likely that the method to find $m_k(A,B,C)$ is to express $k$ in base $2$ (with enough digits padded by leading zeros if necessary to have a total of three digits, since three variables) and then associate the digits to $A,B,C$ in order. So $3$ in base $2$ being $11=011$ we have "off,on,on" i.e. $A$ complemented and $B,C$ not complemented.
You may have need of a different notation $3=(011)_2$ to match this up with the explained answer.
Note that when a number is expressed as a base 2 string of 0's and 1's, the usual notation is to enclose the 0,1 string in parentheses and put a subscript 2 afterwards. So here instead of writing $3=0112$ it is more standard to write $3=(011)_2$. Then the three digits in order are $0,1,1$ which one matches up with $A,B,C$ in that order, so that $A=0,B=1,C=1$ which using 0 for false and 1 for true gives (not A)BC.