curvature$=0$ implies straight line?

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The fundamental theory of differential geometry states that:

If there is a given curvature $\bar{\kappa}(s)>0$ and torsion $\bar{\tau}(s)$ which both of them are differentiable and continuous in $(a,b)$, then:

1.there exists an arc length parametrized curve $C:r=r(s)$ such that its curvature $\kappa(s)=\bar{\kappa}(s)$ and its torsion $\tau(s)=\bar{\tau}(s)$

2.the above curve $C$ is the only curve in Euclidean space (up to rigid transformation)

The question I want to ask is that why it emphasizes that $\bar{\kappa}(s)>0 $ in $(a,b)$ ? Isn't that $\bar{\kappa}(s)=0 $ means the curve is a straight line? If it is a straight line, the curve must be the only curve in the space.