How do you find the curvature of a curve of $y=2x-x^2$ at the point where $x=1$ ?
If someone could provide me a little step by step, that would be great!
2026-03-31 17:05:53.1774976753
Curvature of a curve
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$$k(x)=\frac{y''}{(1+y'^2)^{3/2}}$$