Cycloid angular parameter solution to an ODE for density fluctuations

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I'm just reading over some Cosmology notes and there is a little ODE solve that I am not quite understanding.

I have an equation of the form:

$$ \ddot{R}=-\frac{GM}{R^{2}} $$

Integrating gives:

$$ \dot{R}^{2}=+\frac{2GM}{R}+\mathcal{E} $$

Where $\mathcal{E}$ is just a constant of integration. The notes are essentially saying that this can be solved with a parameter $\theta$ such that r is given by:

$$ r(\theta)=R_{0}(1-\cos\theta) $$

In terms of density this can be written as:

$$ \dot{R}^{2}=\frac{4\pi{G}}{3}\rho_{0}R^{2} $$

There is also a solution of the form:

$$ \rho(\theta)=\rho_{0}\frac{9(\theta-\sin\theta)^{2}}{2(1-\cos\theta)^{3}} $$

Could anyone run through exactly how this is come about?