1)
Calculate the area of the function bordered by function graph
$f : (0, ∞) → R$, $f (x) = \frac{\sqrt{x}+2}{x+1}$
and axe Ox, lines $x=1$ and $ x =4 $
//On this I get stuck and sqrt(x) under x+1 (but idk if I make it right))
2)$f : [0, 3] → R, f (x) =3x-x^2$
Get $ m ∈ R$ such that the ecuation line $y = mx$ to to separate function subgraph in $2 $multitudes of equal areas
//Here I don't understand what I should do
2) I get it as if you should find the slope (that is find $m$) of the straight line so that the two domains (together with the $x$-axis) painted in different colors in the animation below have the same area.
The total area between $y=3x-x^2$ and the $x$-axis is given by $$ \int_0^3 3x-x^2\,dx. $$ The area under the blue graph but above the orange line is given by... well, I leave it for you to figure that out. I think you can find that out. If not, ask in a comment and I'll give you some hint.