I am really confused with this construction of Bott Class in Page 127, Example 8.4.12
If $V$ is a complex vector space of dimension $n$, we form the complex $$ 0 \rightarrow \wedge^0 V \rightarrow \wedge^1 V \rightarrow \cdots \rightarrow \wedge ^nV \rightarrow 0 $$ of trivial vector bundles over $V$.
What does this mean? So we have $n$ trivial vector bundles, $V \times \Bbb C^{\binom{n}{k}}$?
The map $\wedge^pV \rightarrow \wedge^{p+1}V$ is given by $w \mapsto v \wedge w$. Now we pass to complex conjugate bundles. IT is clear that if $f:V \rightarrow W$ is a $\Bbb C$ linear map then $f:\bar{V} \rightarrow \bar{W}$.
What does $\bar{V}$ mean? Where do we use "passing to the complex conjugate"?
Denote the resulting class $b_V \in K^0(DV,DS)$.
(i) How is $b_V$ induced from all the things above? Is this by the wrapping defined on pg 126?
(ii) how is $b_V$ dependent on $f$ or $W$.