Definition of laplace to solve a unit step function equation

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i have watched some youtube videos on how to solve this equation, but im i now stuck. Can somebody tell me how to move on next and why?

$$f(t) = u(t-b)sin(a(t-b))$$ $$F(s) = \int_0^\infty \! e^{-st}u(t-b)sin(a(t-b)) \, \mathrm{d}t.$$ $$= \int_b^\infty \! e^{-st}sin(a(t-b)) \, \mathrm{d}t.$$ $$ = \int_0^\infty \! e^{-s(\frac{v}{a}+b)}sin(v) \, \mathrm{d}v.$$ $$ = e^{-sb}\int_0^\infty \! e^{-(\frac{s}{a})}sin(v) \, \mathrm{d}v.$$