Show that $$DIV(A)=\lim_{\Delta s\rightarrow0}\frac{\displaystyle\int\int_{\Delta v}A\cdot nds}{\Delta v}$$and, $$ROT(A)\cdot n=\lim_{\Delta s\rightarrow 0}\frac{\displaystyle\oint_{C}A\cdot dr}{\Delta s}$$ Is there a demonstration for these results? One suggestion they gave me is to use the mean value theorem for integrals.
Any suggestions?
are NOT consequences of the ordinary definition of the divergence and rotational of a vector field: they are more general since they require only the integrability of the vector field $A$ and no differentiability nor continuity conditions. Thus the standard definition of those vector operators follows easily from them, since considering
$$DIV(A)=\dfrac{\partial A_x}{\partial x}+\dfrac{\partial A_y}{\partial y}+\dfrac{\partial A_z}{\partial z} \tag1$$
$$ROT(A)= \left| {\begin{array}{*{20}{c}}{\vec i}&{\vec j}&{\vec k}\\{\displaystyle \frac{\partial }{{\partial x}}}&{\displaystyle \frac{\partial }{{\partial y}}}&{\displaystyle \frac{\partial }{{\partial z}}}\\A_x&A_y&A_z\end{array}} \right|\tag2$$