Denote in $y(x, τ, ξ)$ solution to the Cauchy problem: $$y' = −y + (x − 3)(1 − e^{−y}), y(τ) = ξ$$
Find: $$\frac{∂y(x, 2, ξ)}{∂ξ}|ξ=0$$
How to do it? Any notes?
Denote in $y(x, τ, ξ)$ solution to the Cauchy problem: $$y' = −y + (x − 3)(1 − e^{−y}), y(τ) = ξ$$
Find: $$\frac{∂y(x, 2, ξ)}{∂ξ}|ξ=0$$
How to do it? Any notes?
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